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x^2-150x+10.000=0
We add all the numbers together, and all the variables
x^2-150x+10=0
a = 1; b = -150; c = +10;
Δ = b2-4ac
Δ = -1502-4·1·10
Δ = 22460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{22460}=\sqrt{4*5615}=\sqrt{4}*\sqrt{5615}=2\sqrt{5615}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-2\sqrt{5615}}{2*1}=\frac{150-2\sqrt{5615}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+2\sqrt{5615}}{2*1}=\frac{150+2\sqrt{5615}}{2} $
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